Include a specific implementation of a library

PlatformIO IDE
,
1

Hi!

I have a library with a common interface contained in a header file. It is split into multiple implementation in separate source files.

Lib structure:

- lib
-- example_lib
--- include
---- example_lib.h
--- src
---- impl_a
----- example_lib.cpp
---- impl_b
----- example_lib.cpp
--- example_lib_impl_a_scope.py
--- example_lib_impl_b_scope.py

And in example_lib_impl_a_scope.py:

Import("env")

env.Append(SRC_FILTER=["+<lib/example_lib/src/impl_a/example_lib.cpp>"])

In platformio.ini:

[env:env_that_uses_impl_a]
build_src_filter = 
    +<main-env_that_uses_impl_a.cpp>
extra_scripts =
    pre:lib/example_lib/example_lib_impl_a_scope.py

I have tried adding example_lib_impl_a_scope.py to library.json and then it works/build only the impl_a/example_lib.cpp source file (but doesn’t fulfill what I want since I want to control which implementation to use from platform.ini). However, when calling the script from platform.ini it builds both source files in lib.

How do I accomplish what I want here? I’m sure there is a way.

2

Try to controll it via a macro (build_flags = -D LIB_IMPL_A) instead. Then the documentation example applies directly.

https://docs.platformio.org/en/latest/manifests/library-json/fields/build/extrascript.html

3

Yes, thanks a lot for this solution!