By calling min you are using the std::min template.
The error in eclipse is e.g.
So the problem here is that it cannot find a valid candidate. The std::min template function expects both arguments to be of the same type.
/**
* @brief This does what you think it does.
* @ingroup sorting_algorithms
* @param __a A thing of arbitrary type.
* @param __b Another thing of arbitrary type.
* @return The lesser of the parameters.
*
* This is the simple classic generic implementation. It will work on
* temporary expressions, since they are only evaluated once, unlike a
* preprocessor macro.
*/
template<typename _Tp>
inline const _Tp&
min(const _Tp& __a, const _Tp& __b)
{
// concept requirements
__glibcxx_function_requires(_LessThanComparableConcept<_Tp>)
//return __b < __a ? __b : __a;
if (__b < __a)
return __b;
return __a;
}
However since you are inputting the integer constant 0xf as the righth this interperted as the int type. On the right you have a uint8_t from the array. So those are not compatible. You must cast the left expression to a uint8_t as well.
while ( i < num_channels )
{
printf("%x",min((uint8_t)0xf,values[i]));
++i;
}
However, you don’t need the min function at all right? You set all values of the array to 0 initially and want to print out the number of responses on that channel So why not directly values[i] but only to a maximum of 0xf = 15? The number can get easily larget than 15 because you have num_reps = 100; so you can get at maximum 100 as values[i].